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6.25r^2-100=r^2-4
We move all terms to the left:
6.25r^2-100-(r^2-4)=0
We get rid of parentheses
6.25r^2-r^2+4-100=0
We add all the numbers together, and all the variables
5.25r^2-96=0
a = 5.25; b = 0; c = -96;
Δ = b2-4ac
Δ = 02-4·5.25·(-96)
Δ = 2016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2016}=\sqrt{144*14}=\sqrt{144}*\sqrt{14}=12\sqrt{14}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{14}}{2*5.25}=\frac{0-12\sqrt{14}}{10.5} =-\frac{12\sqrt{14}}{10.5} =-\frac{6\sqrt{14}}{5.25} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{14}}{2*5.25}=\frac{0+12\sqrt{14}}{10.5} =\frac{12\sqrt{14}}{10.5} =\frac{6\sqrt{14}}{5.25} $
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